Alex pushed a library cart (15.0kg) initially at rest with a constant force of 7.5N along a rough horizonta surface. The wagon accelerated at 0.25 m/s². How much work was done over 3.5sec?

Respuesta :

Answer:

  • 11.5 Joules

Explanation:

Given that : Alex pushed a library cart (15.0kg) initially at rest with a constant force of 7.5N along a rough horizonta surface. The wagon accelerated at 0.25 m/s².

The formula to calculate the work done given by,

  • [tex]W = Fd [/tex]

Where ,

  • W is work done
  • F is force (7.5 N)
  • d is displacement

First let's calculate the displacement (d)

Displacement (d) can be calculated by using the kinematics eqn.

[tex]d = ut +\dfrac{1}{2} at^2[/tex]

Where,

  • u is initial velocity (0 m/s as Alex pushed the library cart initially at rest)
  • a is acceleration (0.25 m/s²)
  • t is time (3.5 seconds)

Plugging the required values,

[tex]d = 0(3.5) + \dfrac{1}{2} (0.25)(3.5)^2 [/tex]

[tex]d = 0.125 \times 12.25 [/tex]

[tex]d = 1.53 \: m [/tex]

Now, Calculating the Work done :

  • W = Fd
  • W = 7.5 × 1.53
  • W = 11.5 Joules

Hence, the work done is 11.5 Joules

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