Respuesta :
Answer:
4 inches
Step-by-step explanation:
To find the height of Nadia's cone pinata, we can use the formula for the volume of a cone:
[tex] \Large\boxed{\boxed{V_{\textsf{cone}} = \dfrac{1}{3} \pi r_{\textsf{cone}}^2 h_{\textsf{cone}} }}[/tex]
where:
- [tex] V_{\textsf{cone}} [/tex] is the volume of the cone (which needs to be the same as the volume of Aaron's sphere),
- [tex] \pi [/tex] is a constant (approximately 3.14159),
- [tex] r_{\textsf{cone}} [/tex] is the radius of Nadia's cone,
- [tex] h_{\textsf{cone}} [/tex] is the height of Nadia's cone.
The volume of Aaron's sphere is given by the formula:
[tex] \Large\boxed{\boxed{V_{\textsf{sphere}} = \dfrac{4}{3} \pi r_{\textsf{sphere}}^3 }}[/tex]
where:
- [tex] V_{\textsf{sphere}} [/tex] is the volume of the sphere,
- [tex] r_{\textsf{sphere}} [/tex] is the radius of the sphere.
Since Aaron and Nadia are splitting the candy evenly, the volumes of their pinatas should be equal:
[tex] V_{\textsf{cone}} = V_{\textsf{sphere}} [/tex]
Substituting in the formulas, we get:
[tex] \dfrac{1}{3} \pi r_{\textsf{cone}}^2 h_{\textsf{cone}} = \dfrac{4}{3} \pi r_{\textsf{sphere}}^3 [/tex]
Aaron's sphere has a radius [tex] r_{\textsf{sphere}} [/tex] of 3 inches.
So, substituting [tex] r_{\textsf{sphere}} = 3 [/tex], we get:
[tex] \dfrac{1}{3} \pi r_{\textsf{cone}}^2 h_{\textsf{cone}} = \dfrac{4}{3} \pi (3)^3 [/tex]
Now, we can solve for [tex] h_{\textsf{cone}} [/tex]:
[tex] \dfrac{1}{\cancel{3}} \cancel{\pi} r_{\textsf{cone}}^2 h_{\textsf{cone}} = \dfrac{4}{\cancel{3}}\cancel{ \pi} (3)^3 [/tex]
[tex] r_{\textsf{cone}}^2 h_{\textsf{cone}} = 4(3)^2 [/tex]
[tex] r_{\textsf{cone}}^2 h_{\textsf{cone}} = 36 [/tex]
[tex] h_{\textsf{cone}} = \dfrac{36}{r_{\textsf{cone}}^2} [/tex]
Since [tex] r_{\textsf{cone}} [/tex] is the same as the radius of Aaron's sphere (3 inches):
[tex] h_{\textsf{cone}} = \dfrac{36}{3^2} [/tex]
[tex] h_{\textsf{cone}} = \dfrac{36}{9} [/tex]
[tex] h_{\textsf{cone}} = 4 [/tex]
Therefore, Nadia should make her cone pinata with a height ([tex] h_{\textsf{cone}} [/tex]) of 4 inches.