How do you solve this problem for special right triangles

Answer:
Both sides are equal to [tex]\sqrt{8}[/tex]
Step-by-step explanation:
The other 2 sides will be the exact same because the angles are the same so instead of using a and b in the Pythagorean theorem I will mark both sides as x
[tex]x^2+x^2=4^2[/tex]
[tex]2x^2=16[/tex]
Divide both sides by 2
[tex]x^2=8[/tex]
Square root both sides
[tex]x=\sqrt{8}[/tex]
I hope this helps