Answer:
[tex]\frac{1}{48}[/tex]
Step-by-step explanation:
we have [tex]\frac{(-8)^{-2}}{\frac{3}{4}}=\frac{1}{(-8)^{2}}\cdot\frac{4}{3}=\frac{1}{64}\cdot\frac{4}{3}=\frac{4}{64\cdot 3}=\frac{1}{16\cdot 3}=\frac{1}{48}[/tex]
Remember: [tex]a^{-b}=\frac{1}{a^{b}}[/tex] and
When dividing with a fraction, multiply by the reciprocal value
