x=2
logx+log(x+3)=1
logx(x+3)=log10
x²+3x=10
x²+3x-10=0
a=1 b=3 c=-10
D=b²-4ac=3²-4×1×(-10)=9+40=49
x1= -3+7 /2= 2
x2= -3-7 /2= -5 (this solution is invalid because x is supposed to be x>0)
This are the rules you need to know:
[tex] log_{x}(ab) = log_{x}(a) + log_{x}(b) [/tex]
and
[tex] log_{2}(2) = 1[/tex]
