A 50 kmol h of ethane is fed to the reactor to produce ethylene and hydrogen. If the product kmol

stream contains 13 of ethylene, then what is the molar flow rate of ethane and h hydrogen in the product stream?

kmol

(A) Ethane - 13 , Hydrogen-37 kmol

(B) Ethane-37 kmol , Hydrogen-37 kmol

(C) Ethane-37 , Hydrogen - 50 kmol

(D) Ethane-37 kmol Hydrogen-13 kmol

In the given problem, the product stream contains 13 kmol of ethylene. Since ethylene is produced from ethane, and assuming a complete conversion, the molar flow rate of ethane must be equal to the molar flow rate of ethylene in the product stream. Therefore, Ethane = 13 kmol.

To find the molar flow rate of hydrogen, we need to subtract the ethylene produced from the total ethane fed to the reactor. The total ethane fed is given as 50 kmol, and we already know the ethane produced is 13 kmol. Hence, Hydrogen = Total Ethane - Ethane Produced = 50 kmol - 13 kmol = 37 kmol.

Therefore, the correct answer is (D) Ethane-37 kmol, Hydrogen-13 kmol. This reflects the molar flow rates of ethane and hydrogen in the product stream after the chemical reaction.

Understanding and solving such chemical engineering problems involve applying the principles of stoichiometry and reaction conversions. In this case, recognizing the relationship between the reactant (ethane) and the product (ethylene) allows us to determine the molar flow rates accurately. This problem demonstrates the importance of balancing chemical equations to analyze and quantify reactants and products in a given process.