kemibabajide85 kemibabajide85
  • 27-01-2024
  • Mathematics
contestada

p²-pr-pq+qr÷p²+pr-pq-qr​

Respuesta :

djp6182583 djp6182583
  • 27-01-2024

Answer:

(p-r)÷(p+r)

Step-by-step explanation:

p²-pr-pq+qr÷p²+pr-pq-qr​

= p(p-r)-q(p-r) ÷ p(p+r)-q(p+r)

= (p-q)(p-r)÷ (p-q)(p+r)

= (p-r)÷(p+r)

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