Answer:
Step-by-step explanation:
Since we are asked for the CHANGE of weight we need to build the first derivative of our function W(t).
With [tex]W(t)=0.00001t^{3} -0.006t^{2}+1.004t+6.1[/tex] we get
[tex]W^{`}(t)=0.00003t^{2}-0.012t+1.004[/tex]
Remember: [tex]f(x)=x^{n}= > f^{`}(x)=n\cdot x^{n-1}[/tex]
Since W(t) is for the first 5 years valid, then W`(t) is also valid for the first 5 years and is the answer to the question (3.5 years is in the Intervall [0,5])