Respuesta :
Answer:
Explanation:
a) To convert CH₃CH₂OH to CH₃COOH, you can use the following reagents:
1. Oxidizing agent: One possible reagent is potassium dichromate (K₂Cr₂O₇) in the presence of sulfuric acid (H₂SO₄). This combination can oxidize the primary alcohol (CH₃CH₂OH) to the corresponding carboxylic acid (CH₃COOH).
2. Another option is using Jones reagent, which consists of chromium trioxide (CrO₃) and dilute sulfuric acid (H₂SO₄). It also oxidizes primary alcohols to carboxylic acids.
b) To convert C₆H₆ to C₆H₅Cl, you can use the following reagents:
1. Chlorine gas (Cl₂): C₆H₆ can react with chlorine gas in the presence of a catalyst such as iron(III) chloride (FeCl₃) to form chlorobenzene (C₆H₅Cl).
2. Another option is using a mixture of concentrated sulfuric acid (H₂SO₄) and hydrochloric acid (HCl) as a reagent. This combination can also convert benzene to chlorobenzene.
c) To convert CH₃CH₂COOH to CH₃CHOHCOOH, you can use the following reagents:
1. Reducing agent: Sodium borohydride (NaBH₄) can reduce the carboxylic acid (CH₃CH₂COOH) to the corresponding alcohol (CH₃CHOHCOOH).
2. Another option is using lithium aluminum hydride (LiAlH₄), which is a stronger reducing agent compared to sodium borohydride. It can also convert carboxylic acids to alcohols.
d) To convert CH₃CH₂Br to CH₃CH₂NH₂, you can use the following reagents:
1. Ammonia (NH₃): CH₃CH₂Br can react with ammonia gas in the presence of a strong base such as sodium hydroxide (NaOH) or potassium hydroxide (KOH) to form the primary amine CH₃CH₂NH₂.
2. Another option is using sodium azide (NaN₃) followed by reduction. Sodium azide (NaN₃) converts the alkyl bromide (CH₃CH₂Br) to the corresponding azide (CH₃CH₂N₃), which can be reduced to the primary amine using a reducing agent such as lithium aluminum hydride (LiAlH₄).
Remember, there are multiple reagents that can be used for each transformation, and the ones mentioned here are just a few examples.
