Respuesta :
This probability is going to be the length of segment ST divided by the length of QT so
P(ST)=(42-29)/(42-24)
P(ST)=13/18
As a percentage:
(p/100)=(13/18)
p=1300/18%
p=650/9%
p≈72.2% (to nearest tenth of a percent)
P(ST)=(42-29)/(42-24)
P(ST)=13/18
As a percentage:
(p/100)=(13/18)
p=1300/18%
p=650/9%
p≈72.2% (to nearest tenth of a percent)
Answer:
The correct option is 4.
Step-by-step explanation:
It is given that Point Q is on the coordinate 24, R is on the coordinate 28, S is on the coordinate 29, T is on the coordinate 42.
Total numbers lie on line QT is
[tex]42-24=18[/tex]
The numbers lie on line ST is
[tex]42-29=13[/tex]
The probability that a point chosen at random on QT is on ST is
[tex]P=\frac{\text{The numbers lie on line ST}}{\text{Total numbers lie on line QT}}\times 100[/tex]
[tex]P=\frac{13}{18}}\times 100[/tex]
[tex]P=72.222\approx 72.2\%[/tex]
The probability that a point chosen at random on QT is on ST is 72.2%. Therefore option 4 is correct.