Question

A Ferris wheel has a diameter of 42 feet. It rotates 3 times per minute. Approximately how far will a passenger travel during a 5-minute ride?

132 feet
659 feet
1,978 feet
3,956 feet

Answer 1

we will need to find the circumference (the perimeter of a circle). The formula for the circumference is C=2пr

The diameter is 2r, so we have to divide 42 by two. You get 21 for the radius. We will use 3.14 for the pi.

then you plug it in to the formula

C = 2 (3.14) * 21

The answer is 131.88

Then times that with 3

you get 395.64

but since it has been 5 minutes, then you times it with 5

that's 1,978.2

Answer 2

Approximately 1978 ft a passenger travel during a 5-minute ride and this can be determined by using the formula of the perimeter of a circle.

Given :

A Ferris wheel has a diameter of 42 feet. It rotates 3 times per minute.

The following steps can be used in order to determine the total distance travel by the passenger during a 5 minutes ride:

Step 1 - First determine the perimeter of the circle. The formula of the perimeter of the circle is given by:

$\rm C = 2\pi r$

Step 2 - Now, substitute the value of known terms in the above formula.

$\rm C=2\pi\times(21)$

$\rm C= 131.94\;ft$

Step 3 - In one minute passenger travels:

$\rm =131.94\times 3=395.82\; ft$

Step 4 - So, in three minutes passenger travels:

$=395.82\times5$

= 1978 ft

So, approximately 1978 ft a passenger travel during a 5-minute ride.

For more information, refer to the link given below:

https://brainly.com/question/23450266