Answer:
all numbers that give 62.8 when truncated to 1 decimal place can be represented as n + 0.8, where n is an integer.
Step-by-step explanation:
To find all numbers that give 62.8 when truncated to 1 decimal place, we need to consider the decimal portion of the number.
When a number is truncated to 1 decimal place, it means that any digits beyond the first decimal place are removed without rounding.
So, to find all numbers that give 62.8 when truncated to 1 decimal place, we need to find all numbers that have a decimal portion of 0.8.
One way to represent numbers with a decimal portion of 0.8 is by using the formula:
x = n + 0.8
where n is an integer representing the whole number portion of the number.
For example:
- If n = 62, then the number is 62.8
- If n = 63, then the number is 63.8
- If n = 64, then the number is 64.8
- and so on
Therefore, all numbers that give 62.8 when truncated to 1 decimal place can be represented as n + 0.8, where n is an integer.
