Answer:
To represent the ionic bond formation between aluminum (Al) and chlorine (Cl) using a dot and cross diagram, Do that:
1. Draw the electron dot diagram for aluminum, which has 13 electrons, and the electron dot diagram for chlorine, which has 17 electrons.
2. Aluminum will lose 3 electrons to form a 3+ ion, and chlorine will gain 1 electron to form a 1- ion.
3. The resulting electron dot diagram will show the transfer of three electrons from aluminum to chlorine, thereby forming Al3+ and Cl1- ions.
4. The ionic bond will form between Al3+ and Cl1- due to the attractive force between opposite charges.
This process will illustrate the formation of an ionic bond between aluminum and chlorine, showing the transfer of electrons from one atom to another to achieve a stable, filled outer electron shell.
