Question

Question attached- Area of triangle with surds. ​

Answer 1

Answer:

$6\sqrt{2}$ cm

Step-by-step explanation:

• area of triangle = half of the base x perpendicular height
• Base = $4\sqrt{2}$ divided by 2 = $2\sqrt{2}$
• perpendicular height is not given so we have to use pythagoras' theorem to solve
• c^2=a^2+b^2
• $(3\sqrt{3})^{2} = (3\sqrt{2})^{2} + b^{2}$
• 27= 18 + b^2
• 9=b^2
• b=3
• hence, the area of the triangle is (3)($2\sqrt{2}$)
• = $6\sqrt{2}$