A man saved Birr 16500 in ten year.In each year after the first he saved birr 100 more than he did in preciding year. How much he saved in the first year?​

Respuesta :

Answer: Birr 1200

Step-by-step explanation:

 Let's assume that the amount he saved in the first year is x birr.

In the second year, he saved x + 100 birr.

In the third year, he saved (x + 100) + 100 birr = x + 200 birr.

Following this pattern, in the fourth year, he saved x + 200 + 100 birr = x + 300 birr.

And so on.

Therefore, in the tenth year, he saved x + 900 birr.

The total amount saved after ten years is given as Birr 16500.

So, x + (x + 100) + (x + 200) + ... + (x + 900) = 16500.

This can be simplified as 10x + 4500 = 16500.

Now, we can solve this equation to find the value of x, the amount saved in the first year.

10x = 16500 - 4500 = 12000.

Dividing both sides by 10, x = 1200.

Therefore, he saved Birr 1200 in the first year.

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