Question

A 0.25 kg baseball is given an impulse of 140 Ns. Find the speed of the baseball.​

Answer 1

Answer:

560 m/s

Explanation:

The impulse $\sf (J)$ experienced by an object is defined as the product of the force $\sf (F)$ applied to the object and the time $\sf (Δt)$ during which the force is applied.

Mathematically, it can be expressed as:

$\sf \textsf{J} = F \cdot \Delta t$

The relationship between impulse, mass $\sf (m )$, and velocity $\sf (v)$ is given by the impulse-momentum theorem:

$\sf J = m \cdot v$

Where:

• $\sf ( J )$ is the impulse,
• $\sf ( m )$ is the mass,
• $\sf ( v )$ is the velocity.

In this case, we are given the impulse $\sf ( J = 140 \, \textsf{Ns} )$ and the mass $\sf ( m = 0.25 \, \textsf{kg} )$ of the baseball.

Now, we can use the impulse-momentum theorem to find the velocity $\sf ( v )$ of the baseball.

$\sf 140 \, \textsf{Ns} = (0.25 \, \textsf{kg}) \cdot v$

Now, solve for $\sf ( v )$:

$\sf v = \dfrac{140 \, \textsf{Ns}}{0.25 \, \textsf{kg}}$

$\sf v = 560 \, \textsf{m/s}$

So, the speed of the baseball is $\sf ( 560 \, \textsf{m/s} )$.