Am I right on this one?

Answer:
Yes , c = 39 is correct
Step-by-step explanation:
given
[tex]\sqrt{c-3}[/tex] - 2 = 4 ( add 2 to both sides )
[tex]\sqrt{c-3}[/tex] = 6 ( square both sides to clear the radical )
( [tex]\sqrt{c-3}[/tex] )² = 6²
c - 3 = 36 ( add 3 to both sides )
c = 39