Question

find three consecutive intergers if the sum of the first two is 51 more then the third integer

Answer 1

52, 53, and 54

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Let's assume the first integer is x. The consecutive integers would be x, (x + 1), and (x + 2).

According to the problem, the sum of the first two integers is 51 more than the third integer.

So, we can write the equation as:

• x + (x + 1) = (x + 2) + 51

Simplifying the equation, we have:

• 2x + 1 = x + 53

Subtracting x and 1 from both sides, we get:

• x = 52

Hence, the three consecutive integers are 52, 53, and 54.