Answer:
Option B is correct.
(1 , -5) lies on the graph.
Step-by-step explanation:
Given the points (4,1) and (-2 , -11)
First find the linear equation for the given points.
Equation of line for two points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex]
is given by: [tex]y-y_1 = (\frac{y_2-y_1}{x_2 - x_1}) (x-x_1)[/tex]
Substitute the given points (4,1) and (-2 , -11) in above equation to find the equation of line:
[tex]y-1=(\frac{-11-1}{-2-4})(x-4)[/tex]
or
[tex]y-1=(\frac{-12}{-6})(x-4)[/tex]
or
[tex]y-1=2(x-4)[/tex]
Using distributive property on RHS ( i.e, [tex]a\cdot (b+c) = a\cdot b+ a\cdot c[/tex] )
we have;
y -1 = 2x-8
Add 1 to both sides of an equation;
y-1+1 = 2x-8+1
Simplify:
y = 2x -7
Therefore, the equation of line for the given point is: y =2x - 7 ....[1]
To find which points lies on the graph ( i.e, Line)
Substituting the given options in equation [1] we have;
A . (1,1)
Put x =1 and y =1
[tex]1 = 2\cdot 1 -7 = 2-7[/tex]
1 = -5 which is not true.
Similarly
B. for (1, -5)
[tex]-5= 2\cdot 1 -7 = 2-7[/tex]
-5 = -5 which is true.
C. for (1, 2)
[tex]2= 2\cdot 1 -7 = 2-7[/tex]
2 = -5 which is not true.
And
D. For (1 , -7)
[tex]-7= 2\cdot 1 -7 = 2-7[/tex]
-7 = -5 which is also not true.
Therefore, the only point which lies on the line graph [1] is; (1 ,-5)
