Respuesta :

Answer:

Step-by-step explanation:

To expand the polynomial (x+1) (x+2) (y-3), we can use the distributive property and multiply each term of one polynomial with each term of the other polynomials.

Let's break down the expansion step by step:

1. Multiply the first two polynomials:

(x+1) (x+2) = x(x+2) + 1(x+2)

= x^2 + 2x + x + 2

= x^2 + 3x + 2

. Multiply the result from step 1 with the third polynomial:

(x^2 + 3x + 2) (y-3) = (x^2 + 3x + 2)y + (x^2 + 3x + 2)(-3)

= x^2y + 3xy + 2y - 3x^2 - 9x - 6

Therefore, the expanded form of the polynomial (x+1) (x+2) (y-3) is x^2y + 3xy + 2y - 3x^2 - 9x - 6.

Please note that this expansion is done by multiplying each term of one polynomial with each term of the other polynomials using the distributive property. The final result is obtained by combining like terms.

Answer:

x²y + 3xy - 3x² + 2y - 9x - 6

Step-by-step explanation:

(x + 1)(x + 2)(y - 3)

= (x² + 3x + 2)(y - 3)

= x²y - 3x² + 3xy - 9x + 2y - 6

So, the answer is x²y + 3xy - 3x² + 2y - 9x - 6.

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