A bat flies at a speed 20 m/s towards a fixed wall and sends an ultrasound of frequency 40000 Hz calculate the apparent frequency of the wave when it strikes the wall (speed of sound in air is 340 m/s)

42500 Hz

40250 Hz

44000 Hz

45000 Hz

Respuesta :

Answer:

42,500 Hz

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr) / (c + vs),

where fr is the frequency heard by the receiver,

fs is the frequency emitted at the source,

c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away.  

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

Given:

fs = 40,000 Hz

c = 340 m/s

vr = 0 m/s

vs = -20 m/s

Find: fr

fr = fs (c + vr) / (c + vs)

fr = 40,000 (340 + 0) / (340 − 20)

fr = 42,500 Hz

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