Respuesta :
Answer:
The correct answer is D. [tex]C_{7} H_{5} NO[/tex].
Explanation:
The first step in this process is to convert each of the percentages given into gram values (e.g. out of 100g). This gives us:
70.6 g C, 4.2 g H, 11.8 g N, 13.4 g O
Next, we can use the molar mass of each element to convert the gram amounts above into mole quantities. This step is shown below for each of the elements above.
70.6 g C * 1 mole C/12.01 g C = 5.878 mol C
4.2 g H * 1 mole H/1.01 g H = 4.158 mol H
11.8 g N * 1 mole N/14.01 g N = 0.842 mol N
13.4 g O * 1 mole O/16.00 g O = 0.8375 mol O
Now that we have mole amounts for each element, we need to make these into whole numbers to find the empirical formula. To do this, we should divide each mole amount by the smallest mole amount we calculated in the previous step. In this case, we should divide each amount by 0.84, which is the smallest mole amount (the amount of nitrogen and oxygen).
5.878 mol C/0.84 = 7 mol C
4.158 mol H/0.84 = 5 mol H
0.84 mol N/0.84 = 1 mol N
0.84 mol O/0.84 = 1 mol O
Finally, we should combine this information to create the empirical formula. The final answer is: [tex]C_{7} H_{5} NO[/tex].
For more information on how to find empirical formulas, check out these other questions on Brainly:
https://brainly.com/question/14044066
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