Question

At a middle school, 18% of all students play football and basketball and 32% of all students play football. What is the probability that a student plays basketball given that the student plays football?

Answer 1

P(basketball |plays football) = (18/32)  = .5625 0r 56% rounded

Answer 2

The probability that a student plays basketball given that the student plays football is 56%.

Given that,

• At a middle school, 18% of all students play football and basketball and 32% of all students play football.

Based on the above information, the calculation is as follows:

$= 18\% \div 32\%$

= 56%

Therefore we can conclude that The probability that a student plays basketball given that the student plays football is 56%.

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