Question

there are 2 questions
35 points in total

Given: g(t) = 4t - 1
Find: g(-3)

Given: g(x) = 3x - 3
Find: g(-10)

Answer 1

Answer:

The first = -13

The second= -33

Step-by-step explanation:

g(-3) = 4(-3) - 1 = -12 - 1 = -13

g(-10) = 3(-10) - 3 = -30 - 3 = -33

Answer 2

Answer:

1) $\sf g(-3) = -13$

2) $\sf g(-10) = -33$

Step-by-step explanation:

1)

To find $\sf g(-3)$ for the function $\sf g(t) = 4t - 1$, substitute $\sf -3$ for $\sf t$:

$\sf g(-3) = 4(-3) - 1$

$\sf g(-3) = -12 - 1$

$\sf g(-3) = -13$

So, $\sf g(-3) = -13$.

2)

For the function $\sf g(x) = 3x - 3$, find $\sf g(-10)$ by substituting $\sf -10$ for $\sf x$:

$\sf g(-10) = 3(-10) - 3$

$\sf g(-10) = -30 - 3$

$\sf g(-10) = -33$

So, $\sf g(-10) = -33$.