From the coordinate plane, we can see that the enlarged point A refers to point F, and enlarged point D refers to point I. To solve for this problem, we know that the ratios of each side should be similar (both the original and enlarged). Since the given choices have all y values equal to 7, so we have to look for the enlarged point of point G. Let us call that point as point C.
In this case, we take the ratio of side IF and side FG. First solving for length using distance formula:
IF^2 = (2 – 4)^2 + (-4 - -2)^2
IF^2 = 8
IF = sqrt 8
FG^2 = (7 – 4)^2 + (-2 - -2)^2
FG^2 = 9
FG = 3
Therefore the ratio of IF/FG must be equal to the ratio of DA / AC:
IF / FG = DA / AC
Find DA first:
DA^2 = (-10 - -2)^2 + (-1 -7)^2
DA^2 = 128
DA = sqrt 128
So,
sqrt 8 / 3 = sqrt 128 / AC
AC = 12
Finding for point C: y of point C = 7
AC^2 = (x - -2)^2 + (7 – 7)^2
12^2 = (x + 2)^2
x + 2 = 12
x = 10
Answer:
(10, 7)
