Question

PLEASE HELP WITH GEOMETRY

Answer 1

In the triangle DFС:  ∠DFС = 94° and ∠FDС = 46°
∠FCD = 180 - ∠DFС - ∠FDС = 180 - 94 - 46 = 40°

∠ACD = ∠FCD = 40°

∠ACD is an inscribed angle  
The measure of the intercepted arc is twice that of the inscribed angle ⇒
arc AD = 2 * ∠ACD = 2 * 40 = 80°