An objects accelerates uniformly at a rate of 1.50 m/s^2 East for 10s, if the velocity of the object reaches 25m/s east in this time, what is the initial velocity

Respuesta :

Answer:

To find the initial velocity (\(u\)) of the object, you can use the kinematic equation:

\[ v = u + at \]

where:

- \(v\) is the final velocity (25 m/s),

- \(u\) is the initial velocity (what we're trying to find),

- \(a\) is the acceleration (1.50 m/s²),

- \(t\) is the time (10 seconds).

Now, rearrange the equation to solve for \(u\):

\[ u = v - at \]

Substitute the known values:

\[ u = 25 \, \text{m/s} - (1.50 \, \text{m/s}^2 \times 10 \, \text{s}) \]

\[ u = 25 \, \text{m/s} - 15 \, \text{m/s} \]

\[ u = 10 \, \text{m/s} \]

So, the initial velocity of the object is \(10 \, \text{m/s}\) to the east.

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