A school typically sells 500 yearbooks each year for $50 each.
The economics class does a project and discovers that they can sell 100 more yearbooks for every $5 decrease in price.The revenue for yearbook sales is equal to the number of yearbooks sold times the price of the yearbook.

Let X represent the number of $5 decreases in price. If the expression that represents the revenue is written in the form R(X)=(500+ax)(50-bx). Find the values of a and b.

Respuesta :

Answer: a=100 and b=5


Step-by-step explanation:

Given: A school typically sells 500 yearbooks each year for $50 each.

The economics class discovers that they can sell 100 more yearbooks for every $5 decrease in price.

Let x represents the number of $5 decreases in price.

Then the new price (in dollars)=50-5x

Total yearbook sold=500+100x

If the revenue for yearbook sales is equal to the number of yearbooks sold times the price of the yearbook.

Then the revenue function will be [tex]R(X)=(500+100x)(50-5x)[/tex]

On comparing this with the given revenue expression we get

a=100 and b=5.

In this exercise we have to calculate the values โ€‹โ€‹of A and B, so we have to:

[tex]A=100\\B=5[/tex]

Since the equation is:

[tex]R(X)=(500+ax)(50-bx)[/tex]

And the following information was given:

  • A school typically sells 500 yearbooks each year for $50 each.
  • The economics class discovers that they can sell 100 more yearbooks for every $5 decrease in price.

So knowing that by increasing 100 more books sold this is equal to A and the decrease in value is going to be equal to b.

[tex]R(X)=(500+100x)(50-5x)[/tex]

See more about equation at brainly.com/question/2263981