[tex]\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}
\end{array}\\
t=year
\end{cases}[/tex]
[tex]\bf 1.185\implies 1+0.185\qquad\quad and\quad n=1
\\\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}\implies A=P\left(1+0.185\right)^{nt}\implies A=P\left(1+\frac{0.185}{1}\right)^{1\cdot t}[/tex]
so, the percentage of the rate is 0.185, what's that as a percentage? well, 0.185 * 100, 18.5%.
