Answer:
Step-by-step explanatioSince distance = speed * time, is a constant, s1t1=s2t2
�
1
�
1
=
�
2
�
2
Let the correct time to reach be t hours
s1 = 10 km/hr and t1 = (t + 4/60) hours
s2 = 12 km/hr and t2 = (t - 2/60) hours
Therefore 10∗(t+460)=12∗(t−260)
10
∗
(
�
+
4
60
)
=
12
∗
(
�
−
2
60
)
10t+4060=12t−2460
10
�
+
40
60
=
12
�
−
24
60
2t=6460
2
�
=
64
60
t=3260
�
=
32
60
Substituting t for the LHS gives the distance = 10∗(3260+460)
10
∗
(
32
60
+
4
60
)
= 6 km
