Q. 30 a) Draw a neat and labeled diagram showing refraction of light using Huygen's wave theory b) The primary and secondary coils of a transformer have a self induction of 4 x 10 ^ - 4 * H each and the mutual induction between them is 6 * 10 ^ - 5 * H Find what percentage of flux in the primary reaches the secondary.

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Answer:

Explanation:

To draw a neat and labeled diagram showing refraction of light using Huygen's wave theory, you can follow these steps:

1. Start by drawing a straight line representing the interface between two different mediums, such as air and water.

2. Label one side as "medium 1" (for example, air) and the other side as "medium 2" (for example, water).

3. Draw an incident ray coming from medium 1 and striking the interface at an angle.

4. According to Huygen's wave theory, each point on the wavefront of the incident ray acts as a source of secondary wavelets.

5. Draw a normal line perpendicular to the interface at the point where the incident ray strikes it.

6. Now, draw a refracted ray that passes through the interface and bends towards or away from the normal, depending on the refractive indices of the two mediums.

7. Label the angle of incidence (i) and the angle of refraction (r).

8. Use Snell's law to determine the relationship between the angles of incidence and refraction: n1sin(i) = n2sin(r), where n1 and n2 are the refractive indices of the two mediums.

9. Finally, label the refracted ray, showing how it changes direction after refraction.

b) To find the percentage of flux in the primary coil that reaches the secondary coil in a transformer, you can use the concept of mutual induction.

1. Given that the self-inductance of both the primary and secondary coils is 4 x 10^-4 H each, and the mutual inductance between them is 6 x 10^-5 H, we can use the formula:

M = k * √(L1 * L2)

Where M is the mutual inductance, L1 is the self-inductance of the primary coil, L2 is the self-inductance of the secondary coil, and k is a constant.

2. Rearranging the formula to solve for k:

k = M / √(L1 * L2)

Substituting the given values:

k = 6 x 10^-5 H / √((4 x 10^-4 H) * (4 x 10^-4 H))

3. Calculate the value of k using a calculator or by hand:

k ≈ 0.1875

4. To find the percentage of flux in the primary that reaches the secondary, we can use the formula:

Percentage of flux = (M^2 / L1) * 100

Substituting the known values:

Percentage of flux = (0.1875^2 / 4 x 10^-4 H) * 100

5. Calculate the value of the percentage using a calculator or by hand:

Percentage of flux ≈ 4.6875%

Therefore, approximately 4.6875% of the flux in the primary coil reaches the secondary coil in this transformer.

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