Question

given g(x)=Squareroot x-4 and h(x)=2x-8, what are the restriction on the domain of gofh?

x>?

Answer 1

$g(f(x)) = \sqrt{(2x - 8) - 4}$
$= \sqrt{2x - 12}$

Now, there's a restriction inside the square root
Thus, 2x - 12 ≥ 0
2x ≥ 12
x ≥ 6