Respuesta :
there is no sum for this geometric series. it diverges rather than converges due to the absolute value of the common ratio (r), which is -3, being 3. for a geometric series to have a sum (to converge), the absolute value of r must be less than 1.
(you find r by dividing a2/a1, a3/a2, etc.)
hope this helps
(you find r by dividing a2/a1, a3/a2, etc.)
hope this helps
Σ-3^(n-1) for n=[1,n]
Angie above is correct though as there is no sum for this as an infinite series as r^2>1.
The only time infinite series have a sum is if r^2<1, and that sum is just s=a/(1-r)
Angie above is correct though as there is no sum for this as an infinite series as r^2>1.
The only time infinite series have a sum is if r^2<1, and that sum is just s=a/(1-r)