Question

Which point satisfies both f(x)=2^x and g(x)=3^x (0,1) (0,-1) (1,0) (-1,0)

Answer 1

The only solution for $2^x=3^x$ is $x=0$, so it's either $(0,1)$ or $(0,-1)$.
Both $2^0$ and $3^0$ are equal to 1, so the answer is $(0,1)$.

Answer 2

note that 2^0 = 1  and 3^0 = 1

so  the point must be (0,1)