Question

How many teams of 3 players can be chosen from 8 players?

Answer 1

this is 8C3   =  8!
                     --------
                      5! 3!

A quick way to do this is    8*7*6
                                          -------   =  8*7  = 56
                                          3*2*1

Answer 2

$8C3=\dfrac{8!}{3!5!}=\dfrac{6\cdot7\cdot8}{2\cdot3}=56$