Question

Determine the zeros of the function f(x) = 3x2 – 7x + 1.

Answer 1

The zeros of the function will be when f(x) = 0.
As 0 = 3x^2 - 7x + 1, you can use the quadratic formula to solve, finding that x = (7 + sqrt(37))/2 or (7 - sqrt(37))/2.

Answer 2

Zeros of the given equation $3x^{2} -7x+ 1$ are $\frac{7+\sqrt{37} }{6} \ or \frac{7-\sqrt{37} }{6}$.

What are the zeros of a quadratic equation?

The zeros of a quadratic equation f(x) are all the x-values that make the polynomial equal to zero.

What is quadratic method?

The quadratic formula helps us solve any quadratic equation. First, we bring the equation to the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we plug these coefficients in the formula:

$x = \frac{-b \pm \sqrt{b^{2} -4ac} }{2a}$

According to the given question.

We have a function.

$f(x) = 3x^{2} -7x+1$

To find the zeros of the function equate f(x) = 0.

$3x^{2} -7x+1 = 0$

Solve the above equation by quadratic method.

$x = \frac{7\pm\sqrt{(7)^{2} -4(3)(1)} }{2(3)}$

$\implies x = \frac{7\pm\sqrt{49-12} }{6}$

$\implies x = \frac{7\pm\sqrt{37} }{6}$

$\implies x = \frac{7+\sqrt{37} }{6} \ or \frac{7-\sqrt{37} }{6}$

Hence, zeros of the given equation $3x^{2} -7x+ 1$ are $\frac{7+\sqrt{37} }{6} \ or \frac{7-\sqrt{37} }{6}$.

Find out more information about zeros of a quadratic equation and quadratic method here:

https://brainly.com/question/27349171

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