Answer:
A.[tex]PR^2=PQ^2+QR^2[/tex]
Because [tex]25=9+16[/tex]
Step-by-step explanation:
We are given that
Area of square A=[tex]9[/tex] square units
Are of square B=[tex]16[/tex] square units
Area of square C=[tex]25[/tex] square units
We have to find the relationship between sides of triangle PQR.
Side of square=[tex]\sqrt{Area\;of\;square}[/tex]
Using the formula
Side of square A=[tex]\sqrt{9}[/tex]=3 units
Side of square B=[tex]\sqrt{16}=4[/tex] units
Side of square C=[tex]\sqrt{25}=5[/tex] units
Pythagoras theorem
[tex](hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2[/tex]
Using Pythagoras theorem
[tex]PR^2=PQ^2+QR^2[/tex]
[tex]5^2=3^2+4^2[/tex]
[tex]25=9+16[/tex]
Option A is true