Respuesta :

[tex]\bf \textit{ellipse, horizontal major axis}\\\\ \cfrac{(x-{{ h}})^2}{{{ a}}^2}+\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1 \qquad \begin{cases} center\ ({{ h}},{{ k}})\\ vertices\ ({{ h}}\pm a, {{ k}})\\ \textit{major axis}\ a+a\\ \textit{minor axis}\ b+b \end{cases} \\\\\\ \cfrac{x^2}{25}+\cfrac{y^2}{4}=1\implies \cfrac{(x-0)^2}{5^2}+\cfrac{(y-0)^2}{2^2}=1\quad \begin{cases} h=0\\ k=0\\ a=5\\ b=2 \end{cases}[/tex]

thus, check the picture below.
Ver imagen jdoe0001
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