Question

What equation is solved by the graphed systems of equations? Two linear equations that intersect at the point negative 1, negative 4.

Answer 1

To solve this problem, we have to manually solve for the value of x for each choices or equations. The correct equation will give a value of -1 since the linear equations intersects at point (-1, -4).

1st: 7x + 3 = x + 3

7x – x = 3 – 3

6x = 0

x = 0                (FALSE)

 

2nd: 7x − 3 = x – 3

7x – x = 3 – 3

6x = 0

x = 0                (FALSE)

           

3rd: 7x + 3 = x − 3

7x – x = - 3 – 3

6x = -6

x = -1               (TRUE)

 

4th: 7x − 3 = x + 3

7x – x = 3 + 3

6x = 6

x = 1                (FALSE)

 

Therefore the answer is:

7x + 3 = x − 3

Answer 2

In this exercise, we are going to solve using our knowledge of systems and in this way we will find that the equation that satisfies the points.

As we know that the equation that will satisfy will have to have the values ​​of X=-1, we will solve each one of the alternatives as:

• First equation is:

$7x + 3 = x + 3\\6x = 0\\x = 0$

We realize that the value of x is not what we want so it doesn't satisfy us.

• second equation is:

$7x - 3 = x - 3\\7x- x = 3- 3\\6x = 0\\x = 0$

We realize that the value of x is not what we want so it doesn't satisfy us.

         

• third equation is:

$7x + 3 = x − 3\\6x = -6\\x = -1$

fourth equation is:

$7x − 3 = x + 3\\7x – x = 3 + 3\\6x = 6\\x = 1$

We realize that the value of x is not what we want so it doesn't satisfy us.

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