Question

The following statistics represent weekly salaries at a construction company.
Mean $550. First quartile $480
Median $630 third quartile $700
Mode $605. 91st percentile $891
The most common salary is ?
The salary that half the employees salaries surpass is ?
The percent of employees salary that serve because $700 is ?
Percent of employees salaries that were less than $480 is
The percent of employees salaries this surpass $891 years
if the company has 104 is the total weekly salary of all employees he is $?

I don't know how to solve the questions

Answer 1

Answer:

The most common salary is $605. The salary that half the employees salaries surpass is $630. The percent of employees salary that serve because $700 is 75%. Percent of employees salaries that were less than $480 is 25%. The 9% percent of employees salaries this surpass $891 years. The total weekly salary of 104 employees is 57200.

Step-by-step explanation:

It is given that mean is $550, first quartile is $480,  median is $630, third quartile is $700,  mode is $605 and 91st percentile is $891.

First quartile is at 25% of the data, median is at 50% of the data, third quartile is at 75% of the data.

The mode of a set of data values is the value that occurs most often.

The most common salary is mode, therefore the most common salary is $605.

The salary that half the employees salaries surpass is $630. Because median is the half of the data.

The percent of employees salary that serve because $700 is 75%. Because $700 is third quartile.

Percent of employees salaries that were less than $480 is 25%. Because $480 is first quartile.

The percent of employees salaries this surpass $891 years is 9%. Because $891 is 91 percentile. Therefore 9% employees get more than $891.

If the company has 104 employees than the total salary of employees is

$104\times 550=57200$

because means is $550, therefore the total weekly salary of 104 employees is 57200.

Answer 2

The most common salary is $605USD$.

The salary that half the employees' salaries surpass is $630USD$.

The percent of employees salary that serves because $700USD$ is $75$%.

The percent of employees' salaries that were less than $480USD$ is $25$%.

The $9$% percent of employees' salaries surpass $891USD$ years.

The total weekly salary of $104$ employees is $57200$.

Given Mean is $550USD$, the first quartile is $480USD$.

The Median is $630USD$, the third quartile is $700USD$, the Mode is $605 USD$ and the $91st$ percentile is $891USD$.

The first quartile is at $25$% of the data, the median is at $50$% of the data, the third quartile is at $75$% of the data.

The mode of a set of data values is the value that occurs most often, So the most common salary is a mode, therefore the most common salary is $605USD$.

As the median is half of the data, the salary that half of the employees' salaries surpass is $630USD$.

Given that $700USD$  is the third quartile, so the percent of employees ' salary that serves

The Percent of employees' salaries that were less than is % as  first quartile.

The percent of employees salaries this surpass $891 years is $9$ %. Because $891USD$ is $91$ percentile. Therefore more than $891USD$.

If the company has $104$ employees then the total salary of employees is

$104\times550=57200$ because means is $550USD$, therefore the total weekly salary of $104$ employees is $57200 USD$.

Therefore, the most common salary is $605USD$. The salary that half the employees' salaries surpass is $630USD$. The percent of employees salary that serves because $700USD$ is $75$%. The percent of employees' salaries that were less than $480USD$ is $25$%.The $9$% percent of employees' salaries surpass $891USD$ years and the total weekly salary of $104$ employees is $57200$$USD$.

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