Respuesta :

[tex] \cfrac{(4g^3h^2k^4)^3}{8g^3h^2}-(h^5k^3)^5= \cfrac{64g^9h^6k^{12}}{8g^3h^2}-h^{25}k^{15}= 8g^6h^4k^{12}-h^{25}k^{15}[/tex]

Given expression:[tex]\frac{\left(4g^3h^2k^4\right)^3}{8g^3h^2}-\left(h^5k^3\right)^5[/tex]

[tex]\left(4g^3h^2k^4\right)^3:\quad 2^6g^9h^6k^{12}[/tex]

[tex]8:\quad 2^3[/tex]

[tex]\frac{\left(4g^3h^2k^4\right)^3}{8g^3h^2}=\frac{2^6g^9h^6k^{12}}{2^3g^3h^2}[/tex]

[tex]=2^3g^6h^4k^{12}[/tex]

[tex]\left(h^5k^3\right)^5=h^{25}k^{15}[/tex]

[tex]\frac{\left(4g^3h^2k^4\right)^3}{8g^3h^2}-\left(h^5k^3\right)^5=2^3g^6h^4k^{12}-h^{25}k^{15}[/tex]

[tex]=8g^6h^4k^{12}-h^{25}k^{15}[/tex]

Therefore, correct option is 4th option [tex]8g^6h^4k^{12}-h^{25}k^{15}[/tex].

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