Question

20 PTS!!!David's company reimburses his expenses on food, lodging, and conveyance during business trips. The company pays $60 a day for food and lodging and $0.65 for each mile traveled. David drove 600 miles and was reimbursed $3,390. Part A: Create an equation that will determine the number of days on the trip. (3 points) Part B: Solve this equation justifying each step with an algebraic property of equality. (6 points) Part C: How many days did David spend on this trip? (1 point)

Answer 1

Part A)

$60 for each day of the trip (d) + $0.65 * the number of miles (600 mi) = the total cost ($3390):

$60d + 390 = 3390$

Part B)

$60d + 390 = 3390$ (Given equation)
$60d + 390 - 390 = 3390 - 390$ (Subtraction property of Inequalities)
$60d = 3000$ (Simplification)
$\frac{60d}{60} = \frac{3000}{60}$ (Division property of inequalities)
$d = 50$ (Simplification)

Part C)

David spent 50 days on his trip.

Answer 2

Answer:

The company pays $60 a day for food and lodging and $0.65 for each mile traveled.

David drove 600 miles and was reimbursed $3,390.

Part A:

Let the number of days of trip be = x

Equation forms:

$600(0.65)+60x=3390$

=> $390+60x=3390$      .......(1)

Part B:

Solving (1) for x.

$390+60x=3390$     (given)

Applying subtraction property of equality;

$60x+390-390=3390-390$

Now simplifying this we get;

$60x=3000$

Applying division property by dividing 60 on both sides, we get

x = 50

Part C:

We get x = 50, so David spent 50 days on the trip.