Question

10(2y+2)−y=2(8y−8)

y= ???

Answer 1

Y = -12
- distribute the 10 into (2y+2)
- distribute 2 into (8y-8)
You will have 20y +20 - y = 16y - 16
- bring the 20 to the other side to get
20y - y = 16y - 36
- subtract y from 2y to get 19y = 16y -36
- bring 16y to the other side to get 3y = -36
- divide 3 from both sides to single out y.
Your final answer is y = -12

Answer 2

10(2y+2)−y=2(8y−8) 
20y + 20 - y = 16y - 16
19y - 16y = -16 - 20
3y = -36
y = -36/3
y = -12