Question

The vertex form of the equation of a parabola is y = (x - 4)2 + 22. What is the standard form of the equation?

Answer 1

First foil (x-4)^2 into x^2-8x+16. You now have y=x^2-8x+16+22. Add 16+22 to get the final equation of y=x^2-8x+38.

Answer 2

The equation in standard form is y = x^2 - 8x + 38

How to write the equation in standard form?

The vertex form of the equation is given as':

y = (x - 4)^2 + 22

Expand the equation

y = x^2 - 8x + 16 + 22

Evaluate the sum

y = x^2 - 8x + 38

Hence, the equation in standard form is y = x^2 - 8x + 38

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