s022213
s022213
28-07-2017
Mathematics
contestada
What is the value of x?
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choixongdong
choixongdong
28-07-2017
CE (CE + CD) = BE(BE + AB)
(x+4) [1+(x+4)] = (x+1)[11+(x+1)]
(x+4)(x+5) = (x+1)(x+12)
x^2 + 9x + 20 = x^2 + 13x + 12
4x = 8
x = 2
answer
x = 2
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Solve for y 7+4y=7-5y+54
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