Answer:
A. Savings account A, because it has more compounding periods per year
Step-by-step explanation:
For compound interest we use formula
[tex]A= P(1+\frac{r}{n})^{n*t}[/tex]
P is the initial amount , r is the rate of interest, n is the period of compounding and t is the number of years
Let initial amount in savings account = $100
Account A : interest rate = 7% and compounded quarterly, year =1
p=100, r=7%= 0.07 , t=1, n=4
[tex]A= 100(1+\frac{0.07}{4})^{4*1}[/tex]
A = $107.19
Amount in account A after 1 year = $107.19
Account B : interest rate = 7% and compounded semiannually, year =1
p=100, r=7%= 0.07 , t=1, n=2
[tex]A= 100(1+\frac{0.07}{2})^{2*1}[/tex]
A = $107.123
Amount in account B after 1 year = $107.12
Amount in account A is more than the amount in account B
because it has more compounding periods per year