Question

The sum of three numbers is 132 . the third number is 7 less than the first. the second number is 3 times the third. what are the numbers?

Answer 1

x+y+z = 132
x = 7+z
y = 3z

(7+z)+3z+z = 132
5z = 132-7
z = 125/5

z = 25 <=====

x = 7+z
x = 7 + 25
x = 39 <=====

y = 3z
y = 3 × 25
y = 75 <=====

hope it helps :)