Question

Determine the ph of a 0.00598 m hclo4 solution. 1.777 6.434 7.566 2.223 3.558

Answer 1

Answer: 2.223
Explanation:
HClO4, also known as perchloric acid, is a very strong. This means we can assume that complete dissociation occurs.
This means that:
[H+] = [HClO4] = 0.00598

pH = -log[H+]
pH = -log[0.00598] = 2.223

Note: The base of the log is 10 (conventionally we don't write the base if it is 10)

Answer 2

$\rm pH=\boxed{\bold{2.223}}$

Further explanation

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.

pH = - log [H⁺]

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.

A solution whose value is different by n has a difference in the concentration of H ions of 10ⁿ.

0.00598 M HClO₄ solution

HClO₄ is a strong ionized acid:

HClO₄ ---> H⁺ + CLO₄⁻

produces 1 H⁺ ion so it has acid valence 1

So we use a strong acid formula to find the pH

[H⁺] = a. M (a = acid valence, M = acid concentration)

[H⁺] = 1. 0.00598

[H⁺] = 5.98 .10⁻³

pH = - log [H⁺]

pH = - log 5.98 .10⁻³

pH = 3- log 5.98

pH = 2,223

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