Question

Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.

Answer 1

Assume the first integer is x, then the rest two are x+2, x+4

So 4x - 6 = (x+2)(x+4)

-> 4x - 6 = x^2 + 6x + 8

-> x^2 + 2x + 14 = 0

Not sure if there are problems with your question description, but apparently no real solutions are possible here.