Question

Consider the function f(x) = (x − 3)2(x + 2)2(x − 1). The zero has a multiplicity of 1. The zero −2 has a multiplicity of?

Answer 1

The zero with a multiplicity of 1 is x = 1, and the zero x = -2 has a multiplicity of 2.

How to find the multiplicity of zeros in a polynomial?

For a general polynomial like:

$p(x) = (x - x_1)^n*(x - x_2)^m*...$

The zero x₁ has a multiplicity of n (same as the exponent in the term where the zero appears), while the zero x₂ has a multiplicity m.

Now let's go to our polynomial:

$f(x) = (x - 3)^2(x + 2)^2(x - 1)$

Here we can see that the only zero with a multiplicity of 1, is x = 1, while the zero x = -2 has a multiplicity of 2.

If you want to learn more about polynomials, you can read:

https://brainly.com/question/4142886

Answer 2

Answer:

first one is 1 and second is 2

Step-by-step explanation:

just got it right